/** * @SuppressWarnings(PHPMD) */ public function reveal($value) { if (is_array($value)) { MockFunctionGenerator::removeDefaultArguments($value); foreach ($value as &$item) { $item = $this->revealer->reveal($item); } return $value; } else { return $this->revealer->reveal($value); } }
/** * Defines the mocked function in the given namespace. * * In most cases you don't have to call this method. enable() is doing this * for you. But if the mock is defined after the first call in the * tested class, the tested class doesn't resolve to the mock. This is * documented in Bug #68541. You therefore have to define the namespaced * function before the first call. Defining the function has no side * effects as you still have to enable the mock. If the function was * already defined this method does nothing. * * @see enable() * @link https://bugs.php.net/bug.php?id=68541 Bug #68541 */ public function define() { $fqfn = $this->getFQFN(); if (function_exists($fqfn)) { return; } $functionGenerator = new MockFunctionGenerator($this); $functionGenerator->defineFunction(); }
/** * @SuppressWarnings(PHPMD) */ public function matches(\PHPUnit_Framework_MockObject_Invocation $invocation) { MockFunctionGenerator::removeDefaultArguments($invocation->parameters); return false; }