/**
* @SuppressWarnings(PHPMD)
*/
public function reveal($value)
{
if (is_array($value)) {
MockFunctionGenerator::removeDefaultArguments($value);
foreach ($value as &$item) {
$item = $this->revealer->reveal($item);
}
return $value;
} else {
return $this->revealer->reveal($value);
}
}
/**
* Defines the mocked function in the given namespace.
*
* In most cases you don't have to call this method. enable() is doing this
* for you. But if the mock is defined after the first call in the
* tested class, the tested class doesn't resolve to the mock. This is
* documented in Bug #68541. You therefore have to define the namespaced
* function before the first call. Defining the function has no side
* effects as you still have to enable the mock. If the function was
* already defined this method does nothing.
*
* @see enable()
* @link https://bugs.php.net/bug.php?id=68541 Bug #68541
*/
public function define()
{
$fqfn = $this->getFQFN();
if (function_exists($fqfn)) {
return;
}
$functionGenerator = new MockFunctionGenerator($this);
$functionGenerator->defineFunction();
}
/**
* @SuppressWarnings(PHPMD)
*/
public function matches(\PHPUnit_Framework_MockObject_Invocation $invocation)
{
MockFunctionGenerator::removeDefaultArguments($invocation->parameters);
return false;
}
