PHP AppBundle\Model Article::fromJson示例

示例#1

文件： APIService.php 项目： chteuchteu/Too-Much-Information

 public function getArticleBySlug($slug)
 {
     $result = $this->doRequest(self::BASE_URI . '/article/getbyslug/' . $slug);
     if (!$result->Success) {
         return null;
     }
     return Article::fromJson($result->Data);
 }