PHP app Subcontractor::findOrFail示例

示例#1

文件： SubcontractorController.php 项目： Vladzor/laravelpractice

 /**
  * Display the specified resource.
  *
  * @param  int $id
  * @return \Illuminate\Http\Response
  */
 public function show($id)
 {
     $subcontractor = App\Subcontractor::findOrFail($id);
     return view('subcontractors.show', compact('subcontractor'));
 }