PHP App\Model UserManager::changePassword示例

示例#1

文件： PasswordFormFactory.php 项目： prcharom/dp-auction-system

 public function formSucceeded(Form $form, $values)
 {
     $userManager = new Model\UserManager($this->user, $this->database);
     $error = $userManager->changePassword($this->id, $values);
     if ($error != null) {
         $form->addError($error);
     }
     if ($form->getPresenter()->isAjax()) {
         $form->getPresenter()->redrawControl('password');
     }
 }