PHP jqGrid::catchException示例

示例#1

文件： ReadRu.php 项目： Moro3/duc

 public function catchException(jqGrid_Exception $e)
 {
     if ($e instanceof jqGrid_Exception_Render) {
         return parent::catchException($e) . "\n" . '$grid = $("<table>"); pager = null; $.extend(null, {';
     }
     return parent::catchException($e);
 }