PHP Sample::get_id示例

 /**
  * @Then id of name :arg1 should be :arg2
  */
 public function idOfNameShouldBe($arg1, $arg2)
 {
     $data = new Sample();
     $rows = $data->get_id($arg1);
     //     print_r( $rows);
     if (sizeof($rows) != 1) {
         throw new Exception("ID is not present.\n");
     } else {
         if ($rows[0]['id'] != $arg2) {
             throw new Exception("ID did not match.\n");
         }
     }
 }

示例#2

显示文件

文件： index.php 项目： sabsen-kol-alone/vz-hackathon

<?php

error_reporting(-1);
ini_set('display_errors', 1);
echo '
    <html>
    <head><title>Sample Page</title></head>
    <body>';
echo '<h1>Sample Page Headline</h1>';
//  phpinfo();
include_once 'Sample.php';
$sample = new Sample();
$sample->init();
$sample->set('Tom', 10);
$sample->set('Joe', 20);
$sample->set('Che', 30);
$names = $sample->get_name(10);
echo "<p>ID: {$names[0]['id']} Name: {$names[0]['name']}</p>";
$names = $sample->get_name(30);
echo "<p>ID: {$names[0]['id']} Name: {$names[0]['name']}</p>";
$ids = $sample->get_id('Joe');
echo "<p>ID: {$ids[0]['id']} Name: {$ids[0]['name']}</p>";
echo '</body></html>';