PHP Models_Jobs::detail示例

示例#1

文件： detail.class.php 项目： manishkhanchandani/mkgxy

 public function execute()
 {
     $request = $_GET;
     $data = array();
     if (empty($request['job_id'])) {
         throw new Exception('Job ID not found');
     }
     $job_id = $request['job_id'];
     $Models_Jobs = new Models_Jobs();
     $data = $Models_Jobs->detail($job_id);
     $this->return = $data;
 }