PHP xmenu_type示例

示例#1

文件： menu_ed.php 项目： abbeet/server39

            ?>
								<option value="<?php 
            echo $xmenu3->id;
            ?>
" <?php 
            if ($xmenu3->id == $value[4]) {
                echo "selected";
            }
            ?>
>
									&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<?php 
            echo $k . '. ' . $xmenu3->name;
            ?>
&nbsp; &nbsp;
								</option><?php 
            $rs4 = xmenu_type("NOT LIKE '%sub%'", $xmenu3->id);
            $l = 1;
            while ($xmenu4 = mysql_fetch_object($rs4)) {
                ?>
									<option value="<?php 
                echo $xmenu4->id;
                ?>
" <?php 
                if ($xmenu4->id == $value[4]) {
                    echo "selected";
                }
                ?>
>
										&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<?php 
                echo $l . '. ' . $xmenu4->name;
                ?>

示例#2

文件： topmenu.php 项目： abbeet/server39

									<li style="width: 150px;"><a class="icon-16-section" href="index.php?p=<?php 
                    echo $topmenu2->id;
                    ?>
"><?php 
                    echo $topmenu2->name;
                    ?>
</a></li><?php 
                } else {
                    ?>
									<li style="width: 150px;" class="node"><a class="icon-16-section"><?php 
                    echo $topmenu2->name;
                    ?>
</a>
										<ul style="width: 150px;"><?php 
                    while ($topmenu3 = mysql_fetch_object($sql3)) {
                        $sql4 = xmenu_type("LIKE '%top%'", $topmenu3->id);
                        $count4 = mysql_num_rows($sql4);
                        if ($count4 == 0) {
                            ?>
													<li style="width: 150px;"><a class="icon-16-category" href="index.php?p=<?php 
                            echo $topmenu3->id;
                            ?>
"><?php 
                            echo $topmenu3->name;
                            ?>
</a></li><?php 
                        } else {
                            ?>
													<li style="width: 150px;" class="node"><a class="icon-16-category"><?php 
                            echo $topmenu3->name;
                            ?>

示例#3

文件： leftmenu.php 项目： abbeet/server39

                    ?>
');<?php 
                } else {
                    ?>
								d.add(<?php 
                    echo $leftmenu2->id;
                    ?>
,<?php 
                    echo $leftmenu2->parent;
                    ?>
,'<?php 
                    echo $leftmenu2->name;
                    ?>
');<?php 
                    while ($leftmenu3 = mysql_fetch_object($sql3)) {
                        $sql4 = xmenu_type("LIKE '%left%'", $leftmenu3->id);
                        $count4 = mysql_num_rows($sql4);
                        if ($count4 == 0) {
                            ?>
										d.add(<?php 
                            echo $leftmenu3->id;
                            ?>
,<?php 
                            echo $leftmenu3->parent;
                            ?>
,'<?php 
                            echo $leftmenu3->name;
                            ?>
','index.php?p=<?php 
                            echo $leftmenu3->id;
                            ?>

示例#4

文件： index_x.php 项目： abbeet/server39

								</ul>
							</dd>
						</dl><?php 
}
if (is_published("submenu")) {
    ?>
						<div id="submenu-box">
							<div class="t"><div class="t"><div class="t"></div></div></div>
								<div class="m">				
									<ul id="submenu"><?php 
    if (@$xmenu->type == 'sub') {
        $parent = @$xmenu->parent;
    } else {
        $parent = $p;
    }
    $rs = xmenu_type("LIKE '%sub%'", $parent);
    $count = mysql_num_rows($rs);
    if ($count == 0) {
        echo "&nbsp;";
    } else {
        while ($submenu = mysql_fetch_object($rs)) {
            ?>
												<li><a href="index.php?p=<?php 
            echo $submenu->id;
            ?>
"><?php 
            echo $submenu->name;
            ?>
</a></li><?php 
        }
    }