PHP existType示例

示例#1

文件： interactionService.php 项目： lindaqq/MeTube

function sendMessage($sender, $receiver, $message)
{
    if (existType($receiver, $sender) == 1) {
        return 0;
    }
    $query = "insert into message (sender, receiver, content) values ('{$sender}', '{$receiver}', '{$message}')";
    $result = mysql_query($query);
    if (!$result) {
        die("sendMessage() failed. Could not query the database: <br />" . mysql_error());
    }
    return 1;
}

示例#2

文件： accountService.php 项目： lindaqq/MeTube

function addContact($userid1, $userid2)
{
    if (existType($userid2, $userid1) == 1) {
        return 0;
    }
    rmExist($userid1, $userid2);
    $query = "insert into contact values ('{$userid1}','{$userid2}', 3)";
    $insert = mysql_query($query);
    if (!$insert) {
        die("Could not insert into the database: <br />" . mysql_error());
    }
    return 1;
}