PHP do_notify示例

示例#1

文件： server.php 项目： ravijoshi0791/vvowproject

function do_logout($user)
{
    $wsid = $user->id;
    mysql_query(sprintf("DELETE FROM contact WHERE wsid='%s'", mysql_real_escape_string($wsid)));
    mysql_query(sprintf("DELETE FROM subscribe WHERE wsid='%s'", mysql_real_escape_string($wsid)));
    $new_request = do_whoisonline($user);
    unset($new_request['code']);
    $new_request['email'] = '*';
    do_notify($new_request, $user);
    return array('code' => 'success');
}

示例#2

文件： restserver.php 项目： ravijoshi0791/vvowproject

function do_delete($user, $request)
{
    $resource = $request['resource'];
    // disable delete if the child resource exists
    $result = mysql_query(sprintf("SELECT rid FROM resource WHERE prid='%s'", mysql_real_escape_string($resource)));
    $result_count = mysql_num_rows($result);
    //mysql_freeresult($result);
    if ($result_count) {
        return array('code' => 'failed', 'reason' => 'this parent resource has children');
    }
    // remove the specific resource.
    mysql_command(sprintf("DELETE FROM resource WHERE rid='%s'", mysql_real_escape_string($resource)));
    do_notify($user, $resource, "DELETE");
    return array('code' => 'success');
}