hasChildren() публичный Метод

public hasChildren ( )
Документация по классу DirectoryResource
Пример #1
0
 public function testHasChildrenDetached()
 {
     $resource = new DirectoryResource($this->fixturesDir . '/dir1');
     $this->assertTrue($resource->hasChildren());
     $resource = new DirectoryResource($this->tempEmptyDir);
     $this->assertFalse($resource->hasChildren());
 }