getHasManyReference() публичный Метод

public getHasManyReference ( $table, $key )
Пример #1
0
 public function getHasManyReference($table, $targetTable = NULL)
 {
     switch ("{$table}:{$targetTable}") {
         case 'posts:props':
             return [$targetTable, 'post_id'];
     }
     parent::getHasManyReference($table, $targetTable);
 }