isExistsAmongTwoUsers() публичный Метод

* check this given two users is already make a conversation
public isExistsAmongTwoUsers ( $user1, $user2 )
$user1
$user2
Пример #1
0
 /**
  * make sure is this conversation exist for this user with currently loggedin user.
  *
  * @param int $userId
  * @return bool|int
  */
 public function isConversationExists($userId)
 {
     if (empty($userId)) {
         return false;
     }
     $user = $this->getSerializeUser($this->authUserId, $userId);
     return $this->conversation->isExistsAmongTwoUsers($user['one'], $user['two']);
 }