<?php
include 'main_class.php';
$obj = new parent_data();
//$result = $obj->select_full('countries');
//$country_result = mysql_fetch_assoc($result);
$user_all = $obj->select_full('register');
//$user_res = mysql_fetch_assoc($user_all);
$username = array();
//if we dont write this then also the below process will work as it suppose to be but if there is no data will come in $username during the loop then error will occur and here we r using $username variable in the jquery process also and functionality of jquery will halt by giving error if the $username will blank and so we define it as array in the starting to overcome all of these problems.
while ($user_res = mysql_fetch_assoc($user_all)) {
$username[] = $user_res['username'];
}
$st_json = json_encode($username);
//json_encode function convert php data into json format,we can use this data in java or json if we want.
?>
<!DOCTYPE html >
<html>
<head>
<style>
.user_exist_cla{
border-color:red;
background-color:red;
}
.error {
color: #D8000C;
background-color: #FFBABA;
}
</style>
<title>A FORM </title>
<?php
include 'main_class.php';
$obj = new parent_data();
$result = $obj->select_full('register');
//$row = mysql_fetch_assoc($result);
/* while($row= mysql_fetch_assoc($result)){
echo '<pre>';
print_r($row);
echo '</pre>';
} */
/* $username = '******';
$password = '******';
$tablename = 'register';
$id = 4;
$dbfname = array('username'=>$username,'password'=>$password);
$obj->update_database($tablename,$dbfname,$id); */
/* $res = mysql_fetch_array($result);
print_r($res);
*/
$str = 'This is THE name';
echo $str_ch = strtolower($str);
