static function TableKeyHasMany($table, $tablePKey, $foreignRef, $foreignKey = false, $foreignClass = 'ADODB_Active_Record')
{
if (!is_array($tablePKey)) {
$tablePKey = array($tablePKey);
}
$ar = new ADODB_Active_Record($table, $tablePKey);
$ar->hasMany($foreignRef, $foreignKey, $foreignClass);
}