PHP alert_and_backの例

コード例 #1

ファイル: insert_typeofmedical.php プロジェクト: thongtank/hospital

<?php

session_start();
if (!isset($_SESSION["admin"]) || $_SESSION["admin"] != "logon") {
    session_unset();
    session_destroy();
    header("Location: index.php");
    exit;
}
include "../php/config/autoload.inc.php";
use config\database;
$db = new database();
$data = array("medical_name" => trim($_POST["medical_name"]));
$sql = "select medical_name from typeOfMedical WHERE medical_name = '" . $data['medical_name'] . "';";
if ($result = $db->query($sql, $rows, $num_rows)) {
    if ($num_rows > 0) {
        alert_and_back("ข้อมูลการรักษานี้มีอยู่แล้ว กรุณาตรวจสอบ . .​ .");
        exit;
    }
    $result = null;
    $rows = null;
    $num_rows = null;
}
$sql = "INSERT INTO `typeOfMedical`(`medical_name`, `date_added`, `added_from`)\n    VALUES ('" . $data['medical_name'] . "',NOW(), '" . $_SESSION["typeOfUser"] . "')";
$result = $db->query($sql, $rows, $num_rows);
if ($result) {
    header("Location: insert_success.php");
} else {
    echo $result . "<BR>";
    echo "<a href='create-typeofmedical.php'>กลับหน้าเพิ่มข้อมูล</a>";
}

コード例 #2

ファイル: insert_medicine.php プロジェクト: thongtank/hospital

session_start();
if (!isset($_SESSION["admin"]) || $_SESSION["admin"] != "logon") {
    session_unset();
    session_destroy();
    header("Location: index.php");
    exit;
}
include '../php/config/autoload.inc.php';
use config\database as db;
$db = new db();
$sql = "select * from medicine where medicine_id = '" . $_POST['medicine_id'] . "';";
$result = $db->query($sql, $rows, $num_rows);
if ($result === true) {
    if ($num_rows > 0) {
        alert_and_back("เลขทะเบียนยาของท่านซ้ำ กรุณาตรวจสอบข้อมูล");
        exit;
    }
}
$result = null;
$rows = null;
$num_rows = null;
$sql = "";
// print '<pre>' . print_r($_POST, 1) . '</pre>';
/*
Array
(
[medicine_id] => 1A 656 2531
[medicine_name_th] => พารา ไซรัป
[medicine_name_eng] => PARA SYRUP
[medicine_type] => ยาน้ำ