function MonthDays($M, $Y)
{
$response = array();
if ($Y >= 0 && $Y < 3000 && $M > 0 && $M <= 12) {
//echo('true <br/>');
$var = IsLeapYear($Y);
$numberOfFebruaryDays = 28;
if ($var == 'true') {
$numberOfFebruaryDays = 29;
}
$array = arrayInit($numberOfFebruaryDays);
$iterator = 0;
foreach ($array as $dayNr) {
$iterator++;
if ($iterator == $M) {
$response = $dayNr;
}
}
}
return $response;
}
</head><?php
/**
* Write a logical function IsLeapYear(Y) that returns True if a year
* Y (a positive integer parameter) is a leap year, and False otherwise.
* Output the return values of this function for five given values of the parameter Y.
* Note that a year is a leap year if it is divisible by 4 except for years that are
* divisible by 100 and are not divisible by 400.
*/
function IsLeapYear($Y)
{
$var = false;
$iterator = 0;
for ($i = 0; $i < 3000; $i += 4) {
if ($Y == $i) {
return 'true';
}
}
return 'false';
}
echo 'is year 2014 a leap year ? ' . IsLeapYear(2014) . '<br/>';
echo 'is year 2015 a leap year ? ' . IsLeapYear(2015) . '<br/>';
echo 'is year 2016 a leap year ? ' . IsLeapYear(2016) . '<br/>';
?>
<span style="display: inline-block">
definition of leap year :
<a href="http://shpargalkablog.ru/2013/10/leap-year.html">
<h1 style='color: blue ; opacity: 0.6 ; font-style: oblique ; font-family: "Arial Black", arial-black'> leap year</h1>
</a>
</span>