Exemple #1
0
function MonthDays($M, $Y)
{
    $response = array();
    if ($Y >= 0 && $Y < 3000 && $M > 0 && $M <= 12) {
        //echo('true <br/>');
        $var = IsLeapYear($Y);
        $numberOfFebruaryDays = 28;
        if ($var == 'true') {
            $numberOfFebruaryDays = 29;
        }
        $array = arrayInit($numberOfFebruaryDays);
        $iterator = 0;
        foreach ($array as $dayNr) {
            $iterator++;
            if ($iterator == $M) {
                $response = $dayNr;
            }
        }
    }
    return $response;
}
Exemple #2
0
</head><?php 
/**
 * Write a logical function IsLeapYear(Y) that returns True if a year
 * Y (a positive integer parameter) is a leap year, and False otherwise.
 * Output the return values of this function for five given values of the parameter Y.
 * Note that a year is a leap year if it is divisible by 4 except for years that are
 * divisible by 100 and are not divisible by 400.
 */
function IsLeapYear($Y)
{
    $var = false;
    $iterator = 0;
    for ($i = 0; $i < 3000; $i += 4) {
        if ($Y == $i) {
            return 'true';
        }
    }
    return 'false';
}
echo 'is year 2014  a leap year ? ' . IsLeapYear(2014) . '<br/>';
echo 'is year 2015  a leap year ? ' . IsLeapYear(2015) . '<br/>';
echo 'is year 2016  a leap year ? ' . IsLeapYear(2016) . '<br/>';
?>

<span style="display: inline-block">
    definition of leap year : &nbsp;
<a href="http://shpargalkablog.ru/2013/10/leap-year.html">
    <h1 style='color: blue ; opacity: 0.6 ; font-style: oblique ; font-family: "Arial Black", arial-black'> leap year</h1>
</a>
</span>