PHP JsonContent::getParserOutput Examples

Example #1

File: JsonContentTest.php Project: rploaiza/dbpedia-latinoamerica

 /**
  * @dataProvider provideDataAndParserText
  */
 public function testFillParserOutput($data, $expected)
 {
     $obj = new JsonContent(FormatJson::encode($data));
     $parserOutput = $obj->getParserOutput($this->getMockTitle(), null, null, true);
     $this->assertInstanceOf('ParserOutput', $parserOutput);
     $this->assertEquals($expected, $parserOutput->getText());
 }