Ejemplos de table_class::find_by_resource_id en PHP

Ejemplo n.º 1

Archivo: news.post.php Proyecto: justin1986/eachbb

 */
//handle the keywords
$keywords = explode('||', $news->keywords);
if ($keywords) {
    foreach ($keywords as $val) {
        if (empty($val)) {
            continue;
        }
        $db->execute("insert into eb_news_keywords (name) values('{$val}') on duplicate key update name='{$val}'");
    }
}
//handle the publish schedule
if (isset($_POST['publish_schedule_date'])) {
    $schedule = new table_class('eb_publish_schedule');
    if ($id) {
        $schedule->find_by_resource_id($id);
    }
    if ($_POST['publish_schedule_date']) {
        $schedule->publish_date = $_POST['publish_schedule_date'];
        $schedule->resource_id = $news->id;
        $schedule->resource_type = 'news';
        $schedule->save();
    } else {
        if ($schedule->id) {
            $schedule->delete();
        }
    }
}
if ($_POST['copy_news']) {
    $news->copy_from = $news->id;
    $news->id = 0;